The variation of stopping potential $V_{0}$ with frequency $\nu$ of incident radiation for a given photosensitive material is a straight line [frequency $\nu$ of incident radiation is greater than threshold frequency $\nu_{0}$]. The slope of this line is . . . . . . .

  • A
    $\frac{h}{\nu}$
  • B
    $\frac{\phi_{0}}{h}$
  • C
    $\frac{h}{e}$
  • D
    $\frac{e}{V_{0}}$

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When photons of energy $h \nu$ fall on a photosensitive surface of work function $E_0$,photoelectrons of maximum kinetic energy $k$ are emitted. If the frequency of radiation is doubled,the maximum kinetic energy will be equal to ($h=$ Planck's constant).

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The slope of the graph between stopping potential and the frequency of incident radiation for the photoelectric effect is . . . . . . .

For the photoelectric effect with incident photon wavelength $\lambda$,the stopping potential is $V_0$. Identify the correct variation$(s)$ of $V_0$ with $\lambda$ and $1/\lambda$.

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