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(B) The Trapezoidal rule for numerical integration is given by:$	ext{Distance} = \int_{0}^{10} v \ dt \approx \frac{h}{2} [y_0 + 2(y_1 + y_2 + y_3 +

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$226$

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(B) The Trapezoidal rule for numerical integration is given by:$	ext{Distance} = \int_{0}^{10} v \ dt \approx \frac{h}{2} [y_0 + 2(y_1 + y_2 + y_3 + y_4) + y_5]$Here, the interval width $h = 2 \ s$.The values are $y_0=0, y_1=12, y_2=16, y_3=20, y_4=35, y_5=60$.Substituting these values into the formula:$	ext{Distance} = \frac{2}{2} [0 + 2(12 + 16 + 20 + 35) + 60]$$= 1 	imes [0 + 2(83) + 60]$$= 166 + 60$$= 226 \ 	ext{m}$.

$t \ (\text{in second})$	$0$	$2$	$4$	$6$	$8$	$10$
$v \ (\text{in m/s})$	$0$	$12$	$16$	$20$	$35$	$60$

The velocity of a particle which starts from rest is given by the following table. The total distance travelled (in metre) by the particle in $10 \ s$, using the Trapezoidal rule, is:
$t \ (\text{in second})$ $0$ $2$ $4$ $6$ $8$ $10$
$v \ (\text{in m/s})$ $0$ $12$ $16$ $20$ $35$ $60$

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The velocity of a particle which starts from rest is given by the following table. The total distance travelled (in metre) by the particle in $10 \ s$, using the Trapezoidal rule, is:$t \ (\text{in second})$$0$$2$$4$$6$$8$$10$$v \ (\text{in m/s})$$0$$12$$16$$20$$35$$60$