The velocity of an object moving in a straight line path is given as a function of time by $v = 6t - 3t^2$,where $v$ is in $m/s$ and $t$ is in $s$. The average velocity of the object between $t = 0$ and $t = 2 \ s$ is

Five particles have speeds $1, 2, 3, 4, 5 \, m/s$. The average velocity of the particles is (in $m/s$):

$A$ person goes from point $P$ to point $Q$ covering $1/3$ of the distance with speed $10 \, km/h$,the next $1/3$ of the distance at $20 \, km/h$,and the last $1/3$ of the distance at $60 \, km/h$. The average speed of the person is ............ $km/h$.

$A$ car moves a distance of $200 \; m$. It covers the first half of the distance at a speed of $40 \; km/h$ and the second half of the distance at a speed of $v$. If the average speed is $48 \; km/h$,the value of $v$ is: (in $; km/h$)

$A$ car travels in a straight line along a road. Its distance $x$ from a stop sign is given as a function of $t$ by the equation $x(t) = \alpha t + \beta t^3$, where $\alpha = 2.0 \ m \ s^{-1}$ and $\beta = 0.01 \ m \ s^{-3}$. Calculate the average velocity of the car in the time interval $t = 2.00 \ s$ to $t = 4.00 \ s$. (in $m \ s^{-1}$)

$A$ body has speed $V, 2V$ and $3V$ in the first $1/3$ of distance $S$,second $1/3$ of $S$,and third $1/3$ of $S$ respectively. Its average speed will be: