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(C) First,identify the resistors in parallel. The $50 \, \Omega$ and $20 \, \Omega$ resistors are connected in parallel.Their equivalent resistance $R

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$70$

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(C) First,identify the resistors in parallel. The $50 \, \Omega$ and $20 \, \Omega$ resistors are connected in parallel.Their equivalent resistance $R_{p}$ is given by:$R_{p} = \frac{50 	imes 20}{50 + 20} = \frac{1000}{70} = \frac{100}{7} \, \Omega$Now,this parallel combination is in series with the $10 \, \Omega$ resistor.The total equivalent resistance of the circuit $R_{eq}$ is:$R_{eq} = 10 + \frac{100}{7} = \frac{70 + 100}{7} = \frac{170}{7} \, \Omega$The total current $I$ in the circuit is:$I = \frac{V}{R_{eq}} = \frac{170}{\frac{170}{7}} = 7 \, 	ext{A}$The voltage $x$ across the $10 \, \Omega$ resistor is given by Ohm's law:$x = I 	imes R = 7 \, 	ext{A} 	imes 10 \, \Omega = 70 \, 	ext{V}$

The voltage across the $10 \, \Omega$ resistor in the given circuit is $x$ volt. The value of $x$ to the nearest integer is..........

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