The volume $V$ of a given mass of monoatomic gas changes with temperature $T$ according to the relation $V = KT^{2/3}$. The work done when temperature changes by $90\,K$ will be $xR$. The value of $x$ is $[R = \text{universal gas constant}]$

  • A
    $50$
  • B
    $60$
  • C
    $48$
  • D
    $72$

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Similar Questions

One mole of a monatomic ideal gas is taken through a cycle $ABCDA$ as shown in the $P-V$ diagram. Column $II$ gives the characteristics involved in the cycle. Match them with each of the processes given in Column $I$.
Column $I$ Column $II$
$(A)$ Process $A \rightarrow B$ $(p)$ Internal energy decreases.
$(B)$ Process $B \rightarrow C$ $(q)$ Internal energy increases.
$(C)$ Process $C \rightarrow D$ $(r)$ Heat is lost.
$(D)$ Process $D \rightarrow A$ $(s)$ Heat is gained.
$(t)$ Work is done on the gas.

An ideal gas having pressure $P$, volume $V$ and temperature $T$ is expanded isothermally to a volume $3V$ and final pressure $P_I$. The same gas is expanded adiabatically to a volume $3V$, the final pressure being $P_A$. The ratio $P_A/P_I$ is $(C_P/C_V = \gamma)$.

Starting with the same initial conditions,an ideal gas expands from volume $V_{i}$ to $V_{f}$ in three different ways. The work done by the gas is $W_{1}$ if the process is purely isothermal,$W_{2}$ if the process is purely adiabatic,and $W_{3}$ if the process is purely isobaric. Then,choose the correct option.

In Column-$I$ processes and in Column-$II$ the first law of thermodynamics are given. Match them appropriately:
Column-$I$ Column-$II$
$(a)$ Adiabatic $(i)$ $\Delta Q = \Delta U$
$(b)$ Isothermal $(ii)$ $\Delta Q = \Delta W$
$(iii)$ $\Delta U = -\Delta W$

One mole of an ideal gas at initial temperature $T$ undergoes a quasi-static process during which the volume $V$ is doubled. During the process,the internal energy $U$ obeys the equation $U = a V^3$,where $a$ is a constant. The work done during this process is

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