The volume of 1, g each of methane (CH_4),eth | vedclass

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Question

(A) Using the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.For butane $(C_4H_{10})$,the molar mass $M = (4 	imes 12) + (10 	imes 1) = 58\,

Vedclass · Accepted Answer

$495$

Vedclass · Answer

(A) Using the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.For butane $(C_4H_{10})$,the molar mass $M = (4 	imes 12) + (10 	imes 1) = 58\, g/mol$.Given $m = 1\, g$,$T = 350\, K$,$P = 1\, atm$,and $R = 0.0821\, L \cdot atm \cdot K^{-1} \cdot mol^{-1}$.$V = \frac{nRT}{P} = \frac{m}{M} 	imes \frac{RT}{P} = \frac{1}{58} 	imes \frac{0.0821 	imes 350}{1} \approx 0.4956\, L$.Since $1\, L = 1000\, cm^3$,the volume is $0.4956 	imes 1000 \approx 495.6\, cm^3$.The closest option is $495\, cm^3$.

The volume of $1\, g$ each of methane $(CH_4)$,ethane $(C_2H_6)$,propane $(C_3H_8)$,and butane $(C_4H_{10})$ was measured at $350\, K$ and $1\, atm$. What is the volume of butane in $cm^{3}$?

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