The volume of a gas is 4 dm^3 at 0^{circ} C. | vedclass

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Question

(C) According to Charles' law,at constant pressure and amount of gas,the volume is directly proportional to the absolute temperature: $V_1 / T_1 = V_2

Vedclass · Accepted Answer

$4.14$

Vedclass · Answer

(C) According to Charles' law,at constant pressure and amount of gas,the volume is directly proportional to the absolute temperature: $V_1 / T_1 = V_2 / T_2$. Initial temperature $T_1 = 0^{\circ} C = 273 \ K$. Final temperature $T_2 = 0^{\circ} C + 10^{\circ} C = 10^{\circ} C = 283 \ K$. Given $V_1 = 4 \ dm^3$. Substituting the values: $4 \ dm^3 / 273 \ K = V_2 / 283 \ K$. $V_2 = (4 	imes 283) / 273 \approx 4.1465 \ dm^3$. Rounding to two decimal places,the volume is $4.14 \ dm^3$.

The volume of a gas is $4 \ dm^3$ at $0^{\circ} C$. Calculate the new volume at constant pressure when the temperature is increased by $10^{\circ} C$. (in $dm^3$)

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