The volume of a liquid is proportional to.... | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Poiseuille's law,the rate of flow of a liquid $(Q)$ through a capillary tube is given by the formula:$Q = \frac{V}{t} = \frac{\pi p R

Vedclass · Accepted Answer

$\frac{p R^4 t}{\eta L}$

Vedclass · Answer

(C) According to Poiseuille's law,the rate of flow of a liquid $(Q)$ through a capillary tube is given by the formula:$Q = \frac{V}{t} = \frac{\pi p R^4}{8 \eta L}$Where:$V$ is the volume of the liquid,$t$ is the time of flow,$p$ is the pressure difference,$R$ is the radius of the tube,$\eta$ is the coefficient of viscosity,$L$ is the length of the tube.Rearranging the formula to solve for the volume $V$:$V = \frac{\pi p R^4 t}{8 \eta L}$Since $\frac{\pi}{8}$ is a dimensionless constant,the volume $V$ is proportional to the remaining terms:$V \propto \frac{p R^4 t}{\eta L}$Therefore,the correct option is $C$.

The volume of a liquid is proportional to......,given its density $\rho$,viscosity $\eta$ and $t$ the time of flow through a capillary tube of length $L$ and radius $R$,with a pressure difference $p$ across its ends.

Similar Questions

In which one of the following cases will the liquid flow in a pipe be most streamlined?

For which of the following Reynolds numbers is a flow considered streamlined (laminar)?

Which of the ratio of forces represents the Reynolds number $Re$?

If $R_e > 1000$,then which type of flow exists? Explain.

If water flows with a velocity of $20 \,cm \,s^{-1}$ in a pipe of radius $2 \,cm$, then the flow is (The coefficient of viscosity of water is $10^{-3} \,kg \,m^{-1} \,s^{-1}$ and density of water is $10^3 \,kg \,m^{-3}$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module