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(B) According to Wien's displacement law,the product of the wavelength of maximum energy emission $(\lambda_m)$ and the absolute temperature $(T)$ is

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$10^7 \ K$

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(B) According to Wien's displacement law,the product of the wavelength of maximum energy emission $(\lambda_m)$ and the absolute temperature $(T)$ is a constant $(b)$: $\lambda_m T = b$ Given: $\lambda_m = 2.93 	imes 10^{-10} \ m$ $b = 2.93 	imes 10^{-3} \ m \ K$ Substituting the values into the formula: $(2.93 	imes 10^{-10} \ m) 	imes T = 2.93 	imes 10^{-3} \ m \ K$ $T = \frac{2.93 	imes 10^{-3}}{2.93 	imes 10^{-10}} \ K$ $T = 10^7 \ K$ Thus,the maximum temperature attained is of the order of $10^7 \ K$.

The wavelength of maximum energy,released during an atomic explosion,was $2.93 \times 10^{-10} \ m$. Given that the Wien's constant is $2.93 \times 10^{-3} \ m \ K$,the maximum temperature attained must be of the order of

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