The work done in blowing a soap bubble of radius $0.2\, m$ is (the surface tension of soap solution being $0.06\, N/m$).
- A$192\pi \times 10^{-4}\,J$
- B$280\pi \times 10^{-4}\,J$
- C$200\pi \times 10^{-3}\,J$
- DNone of these
Explore More
Similar Questions
Work done in increasing the size of a soap bubble from a radius of $3\, cm$ to $5\, cm$ is nearly (Surface tension of soap solution $= 0.03\, N/m$)
Difficult
View SolutionIf $T$ is the surface tension of a soap solution, then the work done in blowing a soap bubble from diameter $D$ to diameter $2D$ is (in $\pi TD^{2}$)
The work done in blowing a soap bubble of $10 \,cm$ radius is ...... $J$ (surface tension of soap solution is $0.03 \,N/m$).
Easy
View Solution$A$ liquid drop of diameter $D$ splits into $3375$ small identical drops. If $S$ is the surface tension of the liquid,then the change in the surface energy in the process is
DifficultAP EAMCET 2025
View SolutionTwo small droplets combine to form a single large drop. What is the ratio of the surface energy of the small droplets to the surface energy of the large drop?
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo