The work done in increasing the length of a $1 \ m$ long wire of cross-section area $1 \ mm^2$ by $1 \ mm$ will be ....... $J$ $(Y = 2 \times 10^{11} \ Nm^{-2})$

  • A
    $0.1$
  • B
    $5$
  • C
    $10$
  • D
    $250$

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