The work function of sodium metal is 4.41 tim | vedclass

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(A) According to Einstein's photoelectric equation: $E = W + K.E._{max}$ $K.E._{max} = E - W$ Energy of incident photon $E = \frac{hc}{\lambda} = \fra

Vedclass · Accepted Answer

$222$

Vedclass · Answer

(A) According to Einstein's photoelectric equation: $E = W + K.E._{max}$ $K.E._{max} = E - W$ Energy of incident photon $E = \frac{hc}{\lambda} = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^{8}}{300 	imes 10^{-9}} = 6.63 	imes 10^{-19} \ J$ Given work function $W = 4.41 	imes 10^{-19} \ J$ $K.E._{max} = 6.63 	imes 10^{-19} - 4.41 	imes 10^{-19} = 2.22 	imes 10^{-19} \ J$ Converting to $10^{-21} \ J$: $2.22 	imes 10^{-19} \ J = 222 	imes 10^{-21} \ J$ Thus,the value is $222$.

The work function of sodium metal is $4.41 \times 10^{-19} \ J$. If photons of wavelength $300 \ nm$ are incident on the metal,the kinetic energy of the ejected electrons will be $\left( \dots \right) \times 10^{-21} \ J$. (Given: $h = 6.63 \times 10^{-34} \ J \cdot s; c = 3 \times 10^{8} \ m/s$)

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