The Young's modulus of the material of a wire | vedclass

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Question

(A) The relation between Young's modulus $(Y)$,modulus of rigidity $(\eta)$,and Poisson's ratio $(\sigma)$ is given by $Y = 2\eta(1 + \sigma)$.Given t

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$3 	imes 10^{12} \ N/m^2$

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(A) The relation between Young's modulus $(Y)$,modulus of rigidity $(\eta)$,and Poisson's ratio $(\sigma)$ is given by $Y = 2\eta(1 + \sigma)$.Given that there is no transverse strain,the Poisson's ratio $\sigma = 0$.Substituting the values,we get $Y = 2\eta(1 + 0) = 2\eta$.Therefore,$\eta = Y / 2$.Given $Y = 6 	imes 10^{12} \ N/m^2$,we have $\eta = (6 	imes 10^{12}) / 2 = 3 	imes 10^{12} \ N/m^2$.

The Young's modulus of the material of a wire is $6 \times 10^{12} \ N/m^2$ and there is no transverse strain in it,then its modulus of rigidity will be

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