The zero of p(x) = x^{2} + 6x + 9 is: | vedclass

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(B) To find the zero of the polynomial $p(x) = x^{2} + 6x + 9$,we set $p(x) = 0$.$x^{2} + 6x + 9 = 0$This is a quadratic expression of the form $a^{2}

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$-3$

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(B) To find the zero of the polynomial $p(x) = x^{2} + 6x + 9$,we set $p(x) = 0$.$x^{2} + 6x + 9 = 0$This is a quadratic expression of the form $a^{2} + 2ab + b^{2} = (a + b)^{2}$.Here,$a = x$ and $b = 3$,so $x^{2} + 2(x)(3) + 3^{2} = (x + 3)^{2}$.Thus,$(x + 3)^{2} = 0$.Taking the square root on both sides,we get $x + 3 = 0$.Therefore,$x = -3$.

The zero of $p(x) = x^{2} + 6x + 9$ is:

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