There are n letters and n addressed envelopes | vedclass

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(B) The total number of ways to place $n$ letters into $n$ envelopes is $n!$.There is only $1$ way in which all letters are placed in their correct co

Vedclass · Accepted Answer

$1 - \frac{1}{n!}$

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(B) The total number of ways to place $n$ letters into $n$ envelopes is $n!$.There is only $1$ way in which all letters are placed in their correct corresponding envelopes.Therefore,the probability that all letters are placed in the correct envelopes is $P(	ext{correct}) = \frac{1}{n!}$.The probability that all the letters are not kept in the right envelope is the complement of the probability that all are in the right envelope.Required probability $= 1 - P(	ext{correct}) = 1 - \frac{1}{n!}$.

There are $n$ letters and $n$ addressed envelopes. The probability that all the letters are not kept in the right envelope,is

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