There are four forces acting at a point P pro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Since point $P$ is at rest,the net force acting on it is zero. We resolve the forces into horizontal $(x)$ and vertical $(y)$ components.For the h

Vedclass · Accepted Answer

$\frac{1}{\sqrt{2}} 	ext{ N}, \frac{3}{\sqrt{2}} 	ext{ N}$

Vedclass · Answer

(A) Since point $P$ is at rest,the net force acting on it is zero. We resolve the forces into horizontal $(x)$ and vertical $(y)$ components.For the horizontal direction ($x$-axis),taking the right direction as positive:$\Sigma F_x = 0 \Rightarrow F_1 + (1 	ext{ N}) \sin 45^{\circ} - (2 	ext{ N}) \sin 45^{\circ} = 0$$F_1 = (2 	ext{ N}) \sin 45^{\circ} - (1 	ext{ N}) \sin 45^{\circ} = (1 	ext{ N}) \sin 45^{\circ} = 1 	imes \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} 	ext{ N}$.For the vertical direction ($y$-axis),taking the upward direction as positive:$\Sigma F_y = 0 \Rightarrow (1 	ext{ N}) \cos 45^{\circ} + (2 	ext{ N}) \cos 45^{\circ} - F_2 = 0$$F_2 = (1 	ext{ N}) \cos 45^{\circ} + (2 	ext{ N}) \cos 45^{\circ} = (3 	ext{ N}) \cos 45^{\circ} = 3 	imes \frac{1}{\sqrt{2}} = \frac{3}{\sqrt{2}} 	ext{ N}$.Thus,$F_1 = \frac{1}{\sqrt{2}} 	ext{ N}$ and $F_2 = \frac{3}{\sqrt{2}} 	ext{ N}$.

There are four forces acting at a point $P$ produced by strings as shown in the figure. Point $P$ is at rest. The forces $F_1$ and $F_2$ are respectively:

Similar Questions

In transgenics,the expression of a transgene in the target tissue is determined by:

The direction ratios of the two lines $AB$ and $AC$ are $1, -1, -1$ and $2, -1, 1$. The direction ratios of the normal to the plane $ABC$ are

$A$ large tank is filled with water to a height $H$. $A$ small hole is made at the base of the tank. It takes $T_1$ time to decrease the height of water to $H/\eta$ (where $\eta > 1$); and it takes $T_2$ time to drain the rest of the water. If $T_1 = T_2$,then the value of $\eta$ is:

$A$ uniform cube is subjected to volume compression. If each side is decreased by $1\%,$ then the bulk strain is

The cubic equation whose roots are the squares of the roots of $x^3-2x^2+10x-8=0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module