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(D) Let the capacity of each container be $x$ litres.In the first container:Milk $= \frac{3}{4}x$ litresWater $= \frac{1}{4}x$ litresIn the second con

Vedclass · Accepted Answer

$41:15$

Vedclass · Answer

(D) Let the capacity of each container be $x$ litres.In the first container:Milk $= \frac{3}{4}x$ litresWater $= \frac{1}{4}x$ litresIn the second container:Milk $= \frac{5}{7}x$ litresWater $= \frac{2}{7}x$ litresOn mixing both,the total quantity of milk is:Milk $= \frac{3}{4}x + \frac{5}{7}x = \frac{21x + 20x}{28} = \frac{41x}{28}$ litresThe total quantity of water is:Water $= \frac{1}{4}x + \frac{2}{7}x = \frac{7x + 8x}{28} = \frac{15x}{28}$ litresTherefore,the required ratio of milk to water is:$\frac{41x}{28} : \frac{15x}{28} = 41:15$

There are two containers of equal capacity. The ratio of milk to water in the first container is $3:1$,and in the second container,it is $5:2$. If they are mixed,the ratio of milk to water in the mixture will be:

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