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(B) The velocity of efflux from a hole at depth $h$ is given by Torricelli's law: $v = \sqrt{2gh}$.According to Newton's second law,the force exerted

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(B) The velocity of efflux from a hole at depth $h$ is given by Torricelli's law: $v = \sqrt{2gh}$.According to Newton's second law,the force exerted by the water jet is $F = \frac{dm}{dt} v = (A ho v) v = A ho v^2$.Substituting $v^2 = 2gh$,we get $F = 2 A ho g h$.Since there are two holes on opposite sides,the forces act in opposite directions. Let the depths of the holes be $h_1$ and $h_2$ such that $h_2 - h_1 = 1 ~m$.The net force is $F_{net} = F_2 - F_1 = A ho (2gh_2) - A ho (2gh_1) = 2 A ho g (h_2 - h_1)$.Given $A = 0.01 ~m^2$,$ho = 1000 ~kg/m^3$,$g = 10 ~m/s^2$,and $(h_2 - h_1) = 1 ~m$.$F_{net} = 2 	imes 0.01 	imes 1000 	imes 10 	imes 1 = 200 ~N$.

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