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(B) According to Torricelli's law, the velocity of efflux from a hole at depth $h$ is $v = \sqrt{2gh}$.The force exerted by the water jet exiting a ho

Vedclass · Accepted Answer

$200$

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(B) According to Torricelli's law, the velocity of efflux from a hole at depth $h$ is $v = \sqrt{2gh}$.The force exerted by the water jet exiting a hole of area $A$ is given by $F = ho A v^2$.For the upper hole at depth $h_1$, the force is $F_1 = ho A (2gh_1)$.For the lower hole at depth $h_2 = h_1 + h$, where $h = 1 \,m$ is the vertical distance between the holes, the force is $F_2 = ho A (2g(h_1 + h))$.Since the holes are on opposite sides, the forces act in opposite directions. The net force $F_{net}$ on the tank is the difference between these forces:$F_{net} = F_2 - F_1 = ho A (2g(h_1 + h)) - ho A (2gh_1) = 2 ho A g h$.Substituting the given values: $ho = 1000 \,kg/m^3$, $A = 0.01 \,m^2$, $g = 10 \,m/s^2$, and $h = 1 \,m$:$F_{net} = 2 	imes 1000 	imes 0.01 	imes 10 	imes 1 = 200 \,N$.

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