There are two identical small holes of cross-sectional area $a$ on the opposite sides of a tank containing a liquid of density $\rho$. The difference in height between the holes is $h$. The tank is resting on a smooth horizontal surface. The horizontal force which will have to be applied on the tank to keep it in equilibrium is

  • A
    $g h \rho a$
  • B
    $\frac{2gh}{\rho a}$
  • C
    $2g h \rho a$
  • D
    $\frac{\rho gh}{a}$

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