There is a $5\,\Omega$ resistance in an $AC$ circuit. An inductance of $0.1\,H$ is connected in series with it. If the equation of the $AC$ $EMF$ is $E = 5\sin(50t)$,then the phase difference between the current and the $EMF$ is:
- A$\frac{\pi}{2}$
- B$\frac{\pi}{6}$
- C$\frac{\pi}{4}$
- D$0$
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