There is a current of 20 , A in a copper wire | vedclass

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(C) The formula for drift velocity $(v_d)$ is given by $v_d = \frac{I}{nAe}$.Given:Current $(I)$ = $20 \, A$Number density of electrons $(n)$ = $10^{2

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$1.25 	imes 10^{-3} \, m/s$

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(C) The formula for drift velocity $(v_d)$ is given by $v_d = \frac{I}{nAe}$.Given:Current $(I)$ = $20 \, A$Number density of electrons $(n)$ = $10^{29} \, m^{-3}$Area of cross-section $(A)$ = $10^{-6} \, m^2$Charge of an electron $(e)$ = $1.6 	imes 10^{-19} \, C$Substituting these values into the formula:$v_d = \frac{20}{10^{29} 	imes 10^{-6} 	imes 1.6 	imes 10^{-19}}$$v_d = \frac{20}{1.6 	imes 10^{29-6-19}}$$v_d = \frac{20}{1.6 	imes 10^4}$$v_d = 12.5 	imes 10^{-4} \, m/s = 1.25 	imes 10^{-3} \, m/s$.

There is a current of $20 \, A$ in a copper wire of $10^{-6} \, m^2$ area of cross-section. If the number of free electrons per cubic meter is $10^{29}$,then the drift velocity is:

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