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(B) Let the $2$-digit number be $10x + y$,where $x$ is the tens digit and $y$ is the units digit.Given that the units digit is twice the tens digit,we

Vedclass · Accepted Answer

$24$

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(B) Let the $2$-digit number be $10x + y$,where $x$ is the tens digit and $y$ is the units digit.Given that the units digit is twice the tens digit,we have $y = 2x$.The sum of the digits is $x + y$. According to the problem,if $2$ is subtracted from this sum,the result is $1/6$ of the number:$x + y - 2 = \frac{1}{6}(10x + y)$Substitute $y = 2x$ into the equation:$x + 2x - 2 = \frac{1}{6}(10x + 2x)$$3x - 2 = \frac{1}{6}(12x)$$3x - 2 = 2x$$x = 2$Since $y = 2x$,we have $y = 2(2) = 4$.Therefore,the number is $10(2) + 4 = 24$.

There is a number consisting of two digits. The digit in the units place is twice that in the tens place,and if $2$ is subtracted from the sum of the digits,the difference is equal to $1/6^{\text{th}}$ of the number. The number is:

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