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(D) The sides of the triangular plot are $a = 200\,m$,$b = 210\,m$,and $c = 290\,m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2}

Vedclass · Accepted Answer

$105000$

Vedclass · Answer

(D) The sides of the triangular plot are $a = 200\,m$,$b = 210\,m$,and $c = 290\,m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2} = \frac{200 + 210 + 290}{2} = \frac{700}{2} = 350\,m$.Using Heron's formula,the area $(A)$ is:$A = \sqrt{s(s-a)(s-b)(s-c)}$$A = \sqrt{350(350-200)(350-210)(350-290)}$$A = \sqrt{350 	imes 150 	imes 140 	imes 60}$$A = \sqrt{35 	imes 10 	imes 15 	imes 10 	imes 14 	imes 10 	imes 6 	imes 10}$$A = \sqrt{35 	imes 15 	imes 14 	imes 6 	imes 10000}$$A = \sqrt{(5 	imes 7) 	imes (3 	imes 5) 	imes (2 	imes 7) 	imes (2 	imes 3) 	imes 10000}$$A = \sqrt{2^2 	imes 3^2 	imes 5^2 	imes 7^2 	imes 100^2} = 2 	imes 3 	imes 5 	imes 7 	imes 100 = 21000\,m^2$.The cost of raising the lawn is $Area 	imes Rate = 21000 	imes 5 = 	ext{Rs. } 105000$.

There is a triangular party plot with side lengths of $200\,m$,$210\,m$,and $290\,m$. Calculate the cost of raising a lawn in that plot at the rate of Rs. $5/m^2$.

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