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(D) The magnetic force on a moving charge is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force $\vec{F}$ is always perpendicular to the v

Vedclass · Accepted Answer

Statement $1$ is true,Statement $2$ is true,Statement $2$ is the correct explanation of Statement $1$.

Vedclass · Answer

(D) The magnetic force on a moving charge is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force $\vec{F}$ is always perpendicular to the velocity vector $\vec{v}$,the work done by the magnetic force on the charge is $W = \int \vec{F} \cdot d\vec{r} = \int \vec{F} \cdot \vec{v} dt = 0$.According to the work-energy theorem,the change in kinetic energy is equal to the work done by the net force.Since the work done is zero,the kinetic energy remains constant.Thus,Statement $1$ is true.Statement $2$ is also true because the magnetic force $\vec{F} = q(\vec{v} 	imes \vec{B})$ is always perpendicular to both $\vec{v}$ and $\vec{B}$,and this perpendicular force is the reason why the speed (and thus kinetic energy) does not change.Therefore,Statement $2$ is the correct explanation of Statement $1$.

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