Three balanced coins are tossed simultaneously. Find the probability of receiving at least two heads.

  • A
    $\frac{1}{2}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{4}$

Explore More

Similar Questions

If $P(A) : P(\bar{A}) = 3 : 4$,then $P(A) =$ .........

Difficult
View Solution

The probability that a non-leap year selected at random will contain $53$ Sundays is

$I$ toss three coins together. The possible outcomes are no heads,$1$ head,$2$ heads and $3$ heads. So,$I$ say that probability of no heads is $\frac{1}{4}$. What is wrong with this conclusion?

Three unbiased coins are tossed simultaneously. Then,the probability of receiving at least two heads is ..........

Find the probability of getting number $2$ on a die when a fair die is thrown.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo