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(D) The total mass of the system is $M = (8 + 5 + 3) \,kg = 16 \,kg$. Since the blocks are connected and move together, the entire system can be treat

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$1.5$

Vedclass · Answer

(D) The total mass of the system is $M = (8 + 5 + 3) \,kg = 16 \,kg$. Since the blocks are connected and move together, the entire system can be treated as a single body of mass $M = 16 \,kg$ moving up the incline with acceleration $a$. The external force applied is $F = 104 \,N$. The component of the total weight acting down the incline is $Mg \sin 30^{\circ}$. Applying Newton's second law to the system: $F - Mg \sin 30^{\circ} = Ma$ $104 - 16 	imes 10 	imes \sin 30^{\circ} = 16a$ $104 - 160 	imes 0.5 = 16a$ $104 - 80 = 16a$ $24 = 16a$ $a = \frac{24}{16} = 1.5 \,m / s^2$. Thus, the acceleration of the blocks is $1.5 \,m / s^2$.

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