Three bulbs of 40, W,60, W,and 100, W are con | vedclass

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(A) The power rating of a bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.From t

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$100\, W$

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(A) The power rating of a bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.From this relation,we can see that $R = \frac{V^2}{P}$.Since the rated voltage $V$ is constant for all bulbs,the resistance $R$ is inversely proportional to the power rating $P$ $(R \propto \frac{1}{P})$.Therefore,the bulb with the highest power rating will have the minimum resistance.Comparing the given power ratings ($40\, W$,$60\, W$,and $100\, W$),the $100\, W$ bulb has the highest power,and thus,it has the minimum resistance.

Three bulbs of $40\, W$,$60\, W$,and $100\, W$ are connected in series to a $220\, V$ supply. Which bulb has the minimum resistance?

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