Three capacitors each of 6,mu F are available | vedclass

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(D) To obtain the minimum capacitance,the capacitors must be connected in series.For $n$ identical capacitors of capacitance $C$ in series,the equival

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$2\,\mu F, 18\,\mu F$

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(D) To obtain the minimum capacitance,the capacitors must be connected in series.For $n$ identical capacitors of capacitance $C$ in series,the equivalent capacitance $C_{s}$ is given by $C_{s} = \frac{C}{n}$.Here,$C = 6\,\mu F$ and $n = 3$,so $C_{s} = \frac{6\,\mu F}{3} = 2\,\mu F$.To obtain the maximum capacitance,the capacitors must be connected in parallel.For $n$ identical capacitors of capacitance $C$ in parallel,the equivalent capacitance $C_{p}$ is given by $C_{p} = n 	imes C$.Here,$C_{p} = 3 	imes 6\,\mu F = 18\,\mu F$.Therefore,the minimum and maximum capacitances are $2\,\mu F$ and $18\,\mu F$ respectively.

Three capacitors each of $6\,\mu F$ are available. The minimum and maximum capacitances which may be obtained are

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