Three capacitors of capacity $C_1, C_2, C_3$ are connected in series. Their total capacity will be

Four identical rectangular plates with length,$l = 2 \, cm$ and breadth,$b = \frac{3}{2} \, cm$ are arranged as shown in the figure. The equivalent capacitance between $A$ and $C$ is $\frac{x \varepsilon_{0}}{d}$. The value of $x$ is (Round off to the Nearest Integer).

$A$ capacitor of capacitance $1 \mu F$ withstands a maximum voltage of $6 kV$,while a capacitor of capacitance $2.0 \mu F$ withstands a maximum voltage of $4 kV$. If the two capacitors are connected in series,then the two capacitors combined can take up a maximum voltage of ... $kV$.

In the figure,three capacitors each of capacitance $6\,pF$ are connected in series. The total capacitance of the combination will be

All six capacitors shown are identical. Each can withstand a maximum of $200\, V$ between its terminals. The maximum voltage that can be safely applied between $A$ and $B$ is.....$V$

Obtain the equivalent capacitance of the network in the figure. For a $300 \; V$ supply,determine the charge and voltage across each capacitor.