Three complexes,[CoCl(NH_3)_5]^{2+} (I),[Co(N | vedclass

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(C) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ of the absorbed light,i.e.,$E = \frac{hc}{\lambda}$.The

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$I > II > III$

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(C) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ of the absorbed light,i.e.,$E = \frac{hc}{\lambda}$.The energy of absorption corresponds to the Crystal Field Splitting Energy ($CFSE$ or $\Delta_o$),which depends on the strength of the ligands.The spectrochemical series order for the ligands is $Cl^- Comparing the complexes:$(I) [CoCl(NH_3)_5]^{2 }$ has $Cl^-$ as a ligand.$(II) [Co(NH_3)_5H_2O]^{3 }$ has $H_2O$ as a ligand.$(III) [Co(NH_3)_6]^{3 }$ has $NH_3$ as a ligand.Since $NH_3$ is a stronger ligand than $H_2O$,and $H_2O$ is stronger than $Cl^-$,the order of $CFSE$ is $(III) > (II) > (I)$.Since $E \propto \Delta_o$,the order of energy absorbed is $(III) > (II) > (I)$.Since $\lambda \propto \frac{1}{E}$,the order of wavelength absorbed is $(I) > (II) > (III)$.

Three complexes,$[CoCl(NH_3)_5]^{2+} (I)$,$[Co(NH_3)_5H_2O]^{3+} (II)$ and $[Co(NH_3)_6]^{3+} (III)$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is

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