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(C) When three fair coins are tossed,the total sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Since the condition is that both heads

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$\frac{1}{2}$

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(C) When three fair coins are tossed,the total sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Since the condition is that both heads and tails must appear,we exclude the cases $HHH$ and $TTT$.Thus,the reduced sample space is $S' = \{HHT, HTH, THH, HTT, THT, TTH\}$,where $n(S') = 6$.We want the probability that exactly one head appears. The favorable outcomes are $E = \{HTT, THT, TTH\}$,where $n(E) = 3$.Therefore,the required probability is $P = \frac{n(E)}{n(S')} = \frac{3}{6} = \frac{1}{2}$.

Three fair coins are tossed. If both heads and tails appear,then the probability that exactly one head appears is:

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