Three moles of an ideal monatomic gas perform | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a $P-T$ diagram,the work done $W$ is given by the area under the process curve. For an ideal gas,$PV = nRT$,so $V = \frac{nRT}{P}$.Processes $1

Vedclass · Accepted Answer

$19.94$

Vedclass · Answer

(A) In a $P-T$ diagram,the work done $W$ is given by the area under the process curve. For an ideal gas,$PV = nRT$,so $V = \frac{nRT}{P}$.Processes $1-2$ and $3-4$ are isochoric (constant volume) because they lie on lines passing through the origin $(P \propto T)$,so $W_{12} = 0$ and $W_{34} = 0$.Processes $2-3$ and $4-1$ are isobaric (constant pressure),so $W = P\Delta V = nR\Delta T$.Total work done $W = W_{12} + W_{23} + W_{34} + W_{41} = 0 + nR(T_3 - T_2) + 0 + nR(T_1 - T_4)$.$W = nR(T_3 - T_2 + T_1 - T_4) = 3 	imes 8.31 	imes (2400 - 800 + 400 - 1200) \, J$.$W = 3 	imes 8.31 	imes (800) \, J = 19944 \, J = 19.944 \, kJ$.

Three moles of an ideal monatomic gas perform a cyclic process as shown in the figure. The temperatures in different states are $T_1 = 400\,K, T_2 = 800\,K, T_3 = 2400\,K$ and $T_4 = 1200\,K$. Determine the work done by the gas during the cycle in $kJ$. (Given $R = 8.31\, J\, mol^{-1} K^{-1}$)

Similar Questions

An ideal gas follows the path shown in the figure. The net work done in the whole cycle is

In the following indicator diagram,the net amount of work done will be

An ideal monoatomic gas is taken through the thermodynamic states $A \to B \to C \to D$ via the paths shown in the figure. If $U_A, U_B, U_C$ and $U_D$ represent the internal energy of the gas in states $A, B, C$ and $D$ respectively,then which of the following is not true?

The pressure $(P)$ versus density $(d)$ graph of an ideal gas is shown in the figure. Choose the correct statement.

An indicator diagram is a ...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module