Three numbers A, B and C are in the ratio of | vedclass

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(C) Let the three numbers be $12x, 15x,$ and $25x$.Given that the sum of these numbers is $312$,we have $12x + 15x + 25x = 312$.$52x = 312$,which give

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$3:10$

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(C) Let the three numbers be $12x, 15x,$ and $25x$.Given that the sum of these numbers is $312$,we have $12x + 15x + 25x = 312$.$52x = 312$,which gives $x = \frac{312}{52} = 6$.Therefore,the numbers are $A = 12 	imes 6 = 72$,$B = 15 	imes 6 = 90$,and $C = 25 	imes 6 = 150$.The difference between $B$ and $A$ is $B - A = 90 - 72 = 18$.The difference between $C$ and $B$ is $C - B = 150 - 90 = 60$.The required ratio is $(B - A) : (C - B) = 18 : 60$.Dividing both terms by $6$,we get $3 : 10$.

Three numbers $A, B$ and $C$ are in the ratio of $12: 15: 25$. If the sum of these numbers is $312$,find the ratio between the difference of $B$ and $A$ and the difference of $C$ and $B$.

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