Three resistances,each of $1\,\Omega$,are joined in parallel. Three such combinations are put in series,then the resultant resistance will be ............. $\Omega$.

  • A
    $9$
  • B
    $3$
  • C
    $1$
  • D
    $1/3$

Explore More

Similar Questions

Three unequal resistors in parallel are equivalent to a resistance of $1 \ \Omega$. If two of them are in the ratio $1:2$ and if no resistance value is fractional,then the largest of the three resistances in ohms is

$A$ network of resistors is connected to a $16\; V$ battery with internal resistance of $1\; \Omega$ as shown in Figure:
$(a)$ Compute the equivalent resistance of the network.
$(b)$ Obtain the current in each resistor.
$(c)$ Obtain the voltage drops $V_{A B}, V_{B C}$ and $V_{C D}$.

Consider the circuit shown below where all resistors are $1 \,k\Omega$. If a current of magnitude $1 \,mA$ flows through the resistor marked $X$,the potential difference measured between points $P$ and $Q$ is ..............$V$.

$A$ wire of resistance $R$ is bent into a circular ring of radius $r$. The equivalent resistance between two points $X$ and $Y$ on its circumference,where the central angle $XOY$ is $\alpha$ (in radians),is given by:

Difficult
View Solution

$10$ resistors,each of resistance $R$,are connected in series to a battery of $emf$ $E$ and negligible internal resistance. When those are connected in parallel to the same battery,the current is increased $n$ times. The value of $n$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo