Three resistors R_{1} = 5 Omega,R_{2} = 10 Om | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a parallel circuit,the potential difference $(V)$ across each resistor is the same.According to Ohm's Law,$I = V / R$.Since $V$ is constant,the

Vedclass · Accepted Answer

$R_{1}$

Vedclass · Answer

(A) In a parallel circuit,the potential difference $(V)$ across each resistor is the same.According to Ohm's Law,$I = V / R$.Since $V$ is constant,the current $(I)$ is inversely proportional to the resistance $(R)$: $I \propto 1 / R$.Therefore,the resistor with the smallest resistance will have the highest current flowing through it.Given $R_{1} = 5 \Omega$,$R_{2} = 10 \Omega$,and $R_{3} = 30 \Omega$,the smallest resistance is $R_{1} = 5 \Omega$.Thus,the highest current flows through $R_{1}$.

Three resistors $R_{1} = 5 \Omega$,$R_{2} = 10 \Omega$,and $R_{3} = 30 \Omega$ are connected in parallel to a $12 \; V$ battery. Which resistor will have the highest current flowing through it?

Similar Questions

What is the magnitude of the electric charge on an electron?

Which law is used to calculate the magnitude of the electric force between two electric charges?

Which of the following materials has the highest number of free electrons?

What is the direction of conventional current?

In an electric circuit,state the relationship between the direction of conventional current and the direction of flow of electrons.

Vedclass Test Series

Exam Paper Generator

Online Exam Module