Three resistors of $5 \, \Omega$,$10 \, \Omega$,and $15 \, \Omega$ are connected in series,and the combination is connected to a battery of $30 \, V$. An ammeter and a voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in the correct order. What is the current flowing through the circuit and the potential difference across the $10 \, \Omega$ resistor?

(N/A) The circuit diagram is as shown in the image.
Given:
$R_1 = 5 \, \Omega$,$R_2 = 10 \, \Omega$,$R_3 = 15 \, \Omega$
$V = 30 \, V$
Since the resistors are connected in series,the total resistance $R$ is:
$R = R_1 + R_2 + R_3$
$R = 5 + 10 + 15 = 30 \, \Omega$
The current $I$ flowing through the circuit is given by Ohm's Law:
$I = V / R = 30 \, V / 30 \, \Omega = 1 \, A$
The potential difference $V'$ across the $10 \, \Omega$ resistor is:
$V' = I \times R_2 = 1 \, A \times 10 \, \Omega = 10 \, V$