Three ships A, B and C sail from England to I | vedclass

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Question

(A) The probabilities of ships $A, B$ and $C$ arriving safely are calculated from the given odds in favor.For ship $A$,the probability $P(A) = \frac{2

Vedclass · Accepted Answer

$\frac{18}{595}$

Vedclass · Answer

(A) The probabilities of ships $A, B$ and $C$ arriving safely are calculated from the given odds in favor.For ship $A$,the probability $P(A) = \frac{2}{2 + 5} = \frac{2}{7}$.For ship $B$,the probability $P(B) = \frac{3}{3 + 7} = \frac{3}{10}$.For ship $C$,the probability $P(C) = \frac{6}{6 + 11} = \frac{6}{17}$.Since the events are independent,the probability of all ships arriving safely is $P(A \cap B \cap C) = P(A) 	imes P(B) 	imes P(C)$.$P(A \cap B \cap C) = \frac{2}{7} 	imes \frac{3}{10} 	imes \frac{6}{17} = \frac{36}{1190} = \frac{18}{595}$.

$P(A)$	$P(B)$	$P(A \cap B)$	$P(A \cup B)$
$0.5$	$0.35$	$.........$	$0.7$

Three ships $A, B$ and $C$ sail from England to India. If the ratio of their arriving safely are $2 : 5, 3 : 7$ and $6 : 11$ respectively,then the probability of all the ships arriving safely is:

Similar Questions

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If ${A_1}, {A_2}, ..., {A_n}$ are any $n$ events,then:

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