Three taps $A, B$ and $C$ can fill a tank in $12, 15$ and $20$ hours respectively. If $A$ is kept open all the time,and $B$ and $C$ are opened for one hour each alternately,how long will it take to fill the tank?

$A, B$ and $C$ are three pipes connected to a tank. $A$ and $B$ together fill the tank in $6 \text{ h}$,$B$ and $C$ together fill the tank in $10 \text{ h}$ and $A$ and $C$ together fill the tank in $12 \text{ h}$. In how much time will $A, B$ and $C$ fill up the tank together?

Three pipes $A, B$ and $C$ can fill a cistern in $10$ $hours$,$12$ $hours$ and $15$ $hours$ respectively. First $A$ was opened. After $1$ $hour$,$B$ was opened and after $2$ $hours$ from the start of $A$,$C$ was also opened. Find the time in which the cistern is just full.

Two pipes can fill an empty tank separately in $24$ $minutes$ and $40$ $minutes$ respectively,and a third pipe can empty $30$ $gallons$ of water per $minute$. If all three pipes are opened,the empty tank becomes full in one $hour$. The capacity of the tank (in $gallons$) is:

Two pipes $A$ and $B$ can separately fill a cistern in $60$ $minutes$ and $75$ $minutes$ respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened,then the cistern is full in $50$ $minutes$. In how much time (in $minutes$) can the third pipe alone empty the cistern?

Pipes $P$ and $Q$ can fill a tank in $5$ and $6 \, h$, respectively, and pipe $C$ can empty it in $3 \, h$. If all the three are opened at $7 \, am$, at what time will two-fifths of the tank be filled?