Three taps are fitted to a cistern. The empty cistern is filled by the first and second taps in $3$ and $4 \, h$,respectively. The full cistern is emptied by the third tap in $5 \, h$. If all three taps are opened simultaneously,the empty cistern will be filled up in?
- A$1 \frac{14}{23} \, h$
- B$2 \frac{14}{23} \, h$
- C$2 \, h \, 40 \, min$
- D$1 \, h \, 56 \, min$
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