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Question

(D) The circuit consists of two parallel branches connected across points $A$ and $B$.The upper branch contains two voltmeters in series with readings

Vedclass · Accepted Answer

$V_1+V_2=V_3$

Vedclass · Answer

(D) The circuit consists of two parallel branches connected across points $A$ and $B$.The upper branch contains two voltmeters in series with readings $V_1$ and $V_2$. The total potential difference across this branch is $V_1 + V_2$.The lower branch contains one voltmeter with reading $V_3$. The potential difference across this branch is $V_3$.Since the two branches are connected in parallel between points $A$ and $B$,the potential difference across both branches must be equal.Therefore,$V_1 + V_2 = V_3$.

Three voltmeters,all having different internal resistances,are connected as shown in the figure. When a potential difference is applied across $A$ and $B$,their readings are $V_1, V_2$,and $V_3$. Choose the correct option.

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