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(C) The average age of $5$ members $3$ years ago was $17$ years.Total age of $5$ members $3$ years ago $= 5 	imes 17 = 85$ years.Present total age of

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$2$

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(C) The average age of $5$ members $3$ years ago was $17$ years.Total age of $5$ members $3$ years ago $= 5 	imes 17 = 85$ years.Present total age of these $5$ members $= 85 + (5 	imes 3) = 85 + 15 = 100$ years.Let the present age of the baby be $x$ years.Now,the family has $6$ members,and their average age is still $17$ years.Total age of $6$ members $= 6 	imes 17 = 102$ years.Therefore,$100 + x = 102$.$x = 102 - 100 = 2$ years.The present age of the baby is $2$ years.

Three years ago,the average age of a family of $5$ members was $17$ years. $A$ baby having been born,the average age of the family is the same today. The present age of the baby is (in years):

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