The time period of a magnet is T. If it is di | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The time period of an oscillating magnet is given by $T = 2\pi \sqrt{\frac{I}{MB_H}}$,where $I$ is the moment of inertia,$M$ is the magnetic momen

Vedclass · Accepted Answer

$T/2$

Vedclass · Answer

(C) The time period of an oscillating magnet is given by $T = 2\pi \sqrt{\frac{I}{MB_H}}$,where $I$ is the moment of inertia,$M$ is the magnetic moment,and $B_H$ is the horizontal component of the magnetic field.When the magnet is cut into four equal parts (two along the axis and two perpendicular to the axis),for each part:The new pole strength $m' = \frac{m}{2}$ and the new length $l' = \frac{l}{2}$.The new magnetic moment $M' = m' 	imes l' = \frac{m}{2} 	imes \frac{l}{2} = \frac{M}{4}$.The new mass $w' = \frac{w}{4}$.The new moment of inertia $I' = \frac{w' (l')^2}{12} = \frac{(w/4) (l/2)^2}{12} = \frac{1}{16} 	imes \frac{wl^2}{12} = \frac{I}{16}$.Substituting these into the formula for the new time period $T'$:$T' = 2\pi \sqrt{\frac{I'}{M'B_H}} = 2\pi \sqrt{\frac{I/16}{(M/4)B_H}} = 2\pi \sqrt{\frac{I}{4MB_H}} = \frac{1}{2} 	imes 2\pi \sqrt{\frac{I}{MB_H}} = \frac{T}{2}$.

The time period of a magnet is $T$. If it is divided into four equal parts along its axis and perpendicular to its axis as shown,then the time period for each part will be

Similar Questions

The periodic time of a magnet in a vibration magnetometer is $T_0$. If the magnet is replaced by another magnet whose moment of inertia is three times and magnetic moment is one-third of the original magnet, then the time period of the new magnet will be:

Two magnets of same size and mass make respectively $10$ and $15$ oscillations per minute at a certain place. The ratio of their magnetic moments is

$A$ thin magnetic iron rod of length $30 \ cm$ is suspended in a uniform magnetic field. Its time period of oscillation is $4 \ s$. It is broken into three equal parts. The time period in seconds of oscillation of one part when suspended in the same magnetic field is

The time period of oscillation of a magnet in a vibration magnetometer is $1.5 \ s$. The time period of oscillation of another magnet similar in size,shape,and mass but having one-fourth magnetic moment than that of the first magnet,oscillating at the same place,will be.....$s$.

When two magnetic moments are compared using the equal distance method,the deflections produced are $45^\circ$ and $30^\circ$. If the lengths of the magnets are in the ratio $1:2$,the ratio of their pole strengths is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module