To an evacuated vessel with a movable piston | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total pressure inside the vessel is equal to the external pressure,which is $P_{total} = 1 \ atm$.The unknown compound exerts a vapour pressur

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) The total pressure inside the vessel is equal to the external pressure,which is $P_{total} = 1 \ atm$.The unknown compound exerts a vapour pressure of $0.68 \ atm$. Since it is in equilibrium with its vapour,the partial pressure of the unknown compound is $P_{unknown} = 0.68 \ atm$.The partial pressure of $He$ is $P_{He} = P_{total} - P_{unknown} = 1 \ atm - 0.68 \ atm = 0.32 \ atm$.Using the ideal gas law for $He$: $PV = nRT$.$0.32 \ atm 	imes V = 0.1 \ mol 	imes 0.0821 \ L \cdot atm \cdot K^{-1} \cdot mol^{-1} 	imes 273 \ K$.$0.32 	imes V = 2.24133$.$V = \frac{2.24133}{0.32} \approx 7.004 \ L$.Thus,the total volume is close to $7 \ L$.

Similar Questions

$A$ gas cylinder contains cooking gas at $14.9 \ atm$ pressure. The pressure gauge of the cylinder reads $12 \ atm$ at $27 \ ^oC$. If the cylinder bursts due to a sudden fire in the building,at what temperature in $^oC$ will the cylinder burst?

Two separate bulbs contain ideal gases $A$ and $B$. The density of gas $A$ is twice that of gas $B$. The molecular mass of $A$ is half that of gas $B$. The two gases are at the same temperature. The ratio of the pressure of $A$ to that of gas $B$ is

Three bulbs are filled with $CH_4$,$CO_2$,and $Ne$ as shown in the picture. The bulbs are connected through pipes of zero volume. When the stopcocks are opened and the temperature is kept constant throughout,the pressure of the system is found to be $...... \ atm$. (Nearest integer)

What does Boyle's Law prove quantitatively? Why?

What is the numerical value of gas constant $R$ in terms of $L \ atm \ K^{-1} \ mol^{-1}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module