To convert 1-butyne to 1-D-butanal,one would | vedclass

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(C) The conversion of $1$-butyne $(CH_3CH_2C \equiv CH)$ to $1-D$-butanal $(CH_3CH_2CH_2CDO)$ requires the introduction of a deuterium atom at the $C-

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$III$

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(C) The conversion of $1$-butyne $(CH_3CH_2C \equiv CH)$ to $1-D$-butanal $(CH_3CH_2CH_2CDO)$ requires the introduction of a deuterium atom at the $C-1$ position and the conversion of the alkyne to an aldehyde. Step $I$ (Sodium amide,then $D_2O$) would produce $1-D$-butyne $(CH_3CH_2C \equiv CD)$. Step $II$ (Hydroboration-oxidation using disiamylborane followed by $H_2O_2/NaOH$) converts $1$-butyne to butanal $(CH_3CH_2CH_2CHO)$. To obtain $1-D$-butanal,one would need to perform hydroboration-oxidation on $1-D$-butyne using $D_2O_2/NaOD$ instead of $H_2O_2/NaOH$. Since the provided reagents in $I$ and $II$ do not lead to the desired product $1-D$-butanal,option $III$ is correct.

To convert $1$-butyne to $1-D$-butanal,one would carry out the following steps :
$(I)$ Sodium amide,then $D_2O$
$(II)$ Disiamylborane,then hydrogen peroxide/sodium hydroxide
$(III)$ The transformation can not be carried out with the indicated reagents.

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To convert $1$-butyne to $1-D$-butanal,one would carry out the following steps :$(I)$ Sodium amide,then $D_2O$$(II)$ Disiamylborane,then hydrogen peroxide/sodium hydroxide$(III)$ The transformation can not be carried out with the indicated reagents.