To establish an instantaneous displacement current of $2\,A$ in the space between two parallel plates of a $1\,\mu F$ capacitor,the potential difference across the capacitor plates will have to be changed at the rate of:

According to Maxwell's hypothesis,a changing electric field gives rise to

$A$ parallel plate capacitor (Figure) made of circular plates each of radius $R=6.0\; cm$ has a capacitance $C=100\; pF$. The capacitor is connected to a $230\; V$ ac supply with a (angular) frequency of $300 \;rad \;s ^{-1}$.
$(a)$ What is the rms value of the conduction current?
$(b)$ Is the conduction current equal to the displacement current?
$(c)$ Determine the amplitude of $B$ at a point $3.0\; cm$ from the axis between the plates.

Write the Ampere-Maxwell law in the form of an equation.

If $\varepsilon_0$ denotes the permittivity of free space and $\phi_{E}$ is the flux of the electric field through the area bounded by the closed surface,then the dimensions of $\left(\varepsilon_0 \frac{d \phi_{E}}{dt}\right)$ are that of

An alternating voltage of amplitude $40 \, V$ and frequency $4 \, kHz$ is applied directly across a capacitor of $12 \, \mu F$. The maximum displacement current between the plates of the capacitor is nearly: (in $ \, A$)