To find out the concentration of SO_{2} in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the class marks $(x_{i})$ for each interval,we use the formula:$x_{i} = \frac{	ext{Upper class limit} + 	ext{Lower class limit}}{2}$The

Vedclass · Accepted Answer

$0.099$

Vedclass · Answer

(B) To find the class marks $(x_{i})$ for each interval,we use the formula:$x_{i} = \frac{	ext{Upper class limit} + 	ext{Lower class limit}}{2}$The class size $(h)$ is $0.04 - 0.00 = 0.04$.Let the assumed mean $(a)$ be $0.14$.We calculate $d_{i} = x_{i} - a$ and $u_{i} = \frac{d_{i}}{h}$.Concentration of $SO_{2}$ $(ppm)$Frequency $(f_{i})$Class mark $(x_{i})$$d_{i} = x_{i} - 0.14$$u_{i} = \frac{d_{i}}{0.04}$$f_{i}u_{i}$$0.00-0.04$$4$$0.02$$-0.12$$-3$$-12$$0.04-0.08$$9$$0.06$$-0.08$$-2$$-18$$0.08-0.12$$9$$0.10$$-0.04$$-1$$-9$$0.12-0.16$$2$$0.14$$0$$0$$0$$0.16-0.20$$4$$0.18$$0.04$$1$$4$$0.20-0.24$$2$$0.22$$0.08$$2$$4$Total$\Sigma f_{i} = 30$$\Sigma f_{i}u_{i} = -31$Using the step-deviation method:Mean $\bar{x} = a + \left( \frac{\Sigma f_{i}u_{i}}{\Sigma f_{i}} ight) 	imes h$$\bar{x} = 0.14 + \left( \frac{-31}{30} ight) 	imes 0.04$$\bar{x} = 0.14 - \frac{1.24}{30}$$\bar{x} = 0.14 - 0.04133...$$\bar{x} \approx 0.09867 \approx 0.099\, ppm$.Thus,the mean concentration of $SO_{2}$ in the air is $0.099\, ppm$.

Number of heartbeats per minute	$65$-$68$	$68$-$71$	$71$-$74$	$74$-$77$	$77$-$80$	$80$-$83$	$83$-$86$
Number of women	$2$	$4$	$3$	$8$	$7$	$4$	$2$

Weight (in kg)	Number of students
Less than $38$	$0$
Less than $40$	$3$
Less than $42$	$5$
Less than $44$	$9$
Less than $46$	$14$
Less than $48$	$28$
Less than $50$	$32$
Less than $52$	$35$

Family size	$1-3$	$3-5$	$5-7$	$7-9$	$9-11$
Number of families	$7$	$8$	$2$	$2$	$1$

Class interval	Frequency
$0-10$	$5$
$10-20$	$x$
$20-30$	$20$
$30-40$	$15$
$40-50$	$y$
$50-60$	$5$
Total	$60$

Daily pocket allowance (in $Rs.$)	$11-13$	$13-15$	$15-17$	$17-19$	$19-21$	$21-23$	$23-25$
Number of children	$7$	$6$	$9$	$13$	$f$	$5$	$4$

Similar Questions

$A$ survey conducted on $20$ households in a locality by a group of students resulted in the following frequency table for the number of family members in a household:
Family size $1-3$ $3-5$ $5-7$ $7-9$ $9-11$
Number of families $7$ $8$ $2$ $2$ $1$

Find the mode of this data.

If the median of the distribution given below is $28.5,$ find the values of $x$ and $y$.
Class interval Frequency
$0-10$ $5$
$10-20$ $x$
$20-30$ $20$
$30-40$ $15$
$40-50$ $y$
$50-60$ $5$
Total $60$

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is $Rs. 18$. Find the missing frequency $f$.
Daily pocket allowance (in $Rs.$) $11-13$ $13-15$ $15-17$ $17-19$ $19-21$ $21-23$ $23-25$
Number of children $7$ $6$ $9$ $13$ $f$ $5$ $4$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Concentration of $SO_{2}$ (in $ppm$)	Frequency
$0.00-0.04$	$4$
$0.04-0.08$	$9$
$0.08-0.12$	$9$
$0.12-0.16$	$2$
$0.16-0.20$	$4$
$0.20-0.24$	$2$