To raise the pitch of a stringed musical inst | vedclass

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(D) The correct answer is $(d)$.Pitch is directly related to the frequency of the sound produced. $A$ higher pitch corresponds to a higher frequency.T

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Both $(b)$ and $(c)$

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(D) The correct answer is $(d)$.Pitch is directly related to the frequency of the sound produced. $A$ higher pitch corresponds to a higher frequency.The frequency $n$ of a vibrating string is given by the formula:$n = \frac{p}{2l} \sqrt{\frac{T}{m}}$where $p$ is the number of loops,$l$ is the length of the string,$T$ is the tension in the string,and $m$ is the mass per unit length.From the relation $n \propto \frac{\sqrt{T}}{l}$,it is clear that:$1$. Increasing the tension $T$ increases the frequency $n$.$2$. Decreasing the length $l$ increases the frequency $n$.Therefore,to raise the pitch,the player can either tighten the string (increase $T$) or shorten the string (decrease $l$).

To raise the pitch of a stringed musical instrument,the player can:

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