To remove myopia (short-sightedness),a lens o | vedclass

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Question

(B) For a myopic eye,the corrective lens must form an image of an object at infinity at the person's far point $(x)$.Using the lens formula: $\frac{1}

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(B) For a myopic eye,the corrective lens must form an image of an object at infinity at the person's far point $(x)$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Here,$u = -\infty$ and $v = -x$ (where $x$ is the distance of the far point).Since $P = \frac{1}{f}$ (in meters),we have $P = \frac{1}{-x}$.Thus,$x = -\frac{1}{P}$.Given $P = -0.66 \, D$ (a concave lens is required for myopia).$x = \frac{1}{0.66} \, m = 1.515 \, m$.Converting to centimeters: $x \approx 151 \, cm \approx 150 \, cm$.

To remove myopia (short-sightedness),a lens of power $0.66 \, D$ is required. The far point of the eye is approximately ....... $cm$.

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