To synthesise 1.0 mole of 2-methylpropan-2-o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of ethyl ethanoate $(CH_{3}COOCH_{2}CH_{3})$ with Grignard reagent $(CH_{3}MgBr)$ proceeds in two steps:$1$. First,$1$ equivalent of

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The reaction of ethyl ethanoate $(CH_{3}COOCH_{2}CH_{3})$ with Grignard reagent $(CH_{3}MgBr)$ proceeds in two steps:$1$. First,$1$ equivalent of $CH_{3}MgBr$ attacks the carbonyl carbon of the ester,leading to the elimination of the ethoxide group and the formation of acetone $(CH_{3}COCH_{3})$.$2$. Second,another equivalent of $CH_{3}MgBr$ attacks the carbonyl carbon of the formed acetone to produce a tertiary alkoxide intermediate $(CH_{3}C(OMgBr)(CH_{3})_{2})$.$3$. Upon acidic workup (hydrolysis),this intermediate yields $2-$methylpropan$-2-$ol.Thus,a total of $2$ equivalents of $CH_{3}MgBr$ are required for the complete conversion of $1$ mole of ethyl ethanoate to $1$ mole of $2-$methylpropan$-2-$ol.

To synthesise $1.0 \ mole$ of $2-$methylpropan$-2-$ol from ethyl ethanoate,how many equivalents of $CH_{3}MgBr$ reagent will be required? (Integer value)

Similar Questions

Benzonitrile on reduction with stannous chloride $(SnCl_2)$ in the presence of hydrochloric acid $(HCl)$ followed by acid hydrolysis forms:

What is the name of the given reaction?
$C_6H_6 + CO + HCl \xrightarrow{Anhyd. AlCl_3} C_6H_5CHO$

In the following reaction sequence,$X$ and $Y$ are:

Which of the following is a Stephen reaction?

Which of the following reactions is best for the preparation of an aldehyde from a primary alcohol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module